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Solved 2009 ICSE Computer Science Paper

Class 10 - ICSE Computer Science Solved Papers

Menu driven - BUZZ Number / GCD Program - ICSE 2009 Computer Science

Write a menu-driven program to accept a number from the user and check whether it is a BUZZ number or to accept any two numbers and print the GCD of them.
a) A BUZZ number is the number which either ends with 7 or is divisible by 7.
b) GCD (Greatest Common Divisor) of two integers is calculated by continued division method. Divide the larger number by the smaller; the remainder then divides the previous divisor. The process is repeated until the remainder is zero. The divisor then results the GCD.

Java 

import java.util.Scanner;
class Menu{
    public static void main(String args[]){
        Scanner in = new Scanner(System.in);
        System.out.println("1. Buzz number");
        System.out.println("2. GCD");
        System.out.print("Enter your choice: ");
        int choice = Integer.parseInt(in.nextLine());
        switch(choice){
            case 1:
            System.out.print("Enter the number: ");
            int n = Integer.parseInt(in.nextLine());
            if(n % 7 == 0 || n % 10 == 7)
                System.out.println("Buzz number");
            else
                System.out.println("Not a Buzz number");
            break;
            case 2:
            System.out.print("First number: ");
            int a = Integer.parseInt(in.nextLine());
            System.out.print("Second number: ");
            int b = Integer.parseInt(in.nextLine());
            while(a % b != 0){
                int rem = a % b;
                a = b;
                b = rem;
            }
            System.out.println("GCD = " + b);
            break;
            default:
            System.out.println("Invalid choice!");
        }
    }
}

Output

 
 OUTPUT 1: 
1. Buzz number
2. GCD
Enter your choice: 1
Enter the number: 17
Buzz number
 
 OUTPUT 2: 
1. Buzz number
2. GCD
Enter your choice: 2
First number: 24
Second number: 12
GCD = 12
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