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Java Programs - Advanced
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Circular Prime Program - Java Program
A Circular Prime is a prime number that remains prime under cyclic shifts of its digits. When the leftmost digit is removed and replaced at the end of the remaining string of digits, the generated number is still prime. The process is repeated until the original number is reached again.
A number is said to be prime if it has only two factors 1 and itself.
Example:
131
311
113
Hence, 131 is a circular prime.
Accept a positive number N and check whether it is a circular prime or not. The new numbers formed after the shifting of the digits should also be displayed.
Test your program with the following data and some random data:
Example 1:
INPUT:
N = 197
OUTPUT:
197
971
719
197 IS A CIRCULAR PRIME.
Example 2:
INPUT:
N = 1193
OUTPUT:
1193
1931
9311
3119
1193 IS A CIRCULAR PRIME.
Example 3:
INPUT:
N = 29
OUTPUT:
29
92
29 IS NOT A CIRCULAR PRIME.
import java.io.*; class CircularPrime{ public static void main(String args[]) throws IOException{ InputStreamReader in = new InputStreamReader(System.in); BufferedReader br = new BufferedReader(in); System.out.print("N = "); int n = Integer.parseInt(br.readLine()); String s = Integer.toString(n); int len = s.length(); boolean status = true; for(int i = 1; i <= len; i++){ if(!isPrime(n)) status = false; System.out.println(n); s = s.substring(1) + s.charAt(0); n = Integer.parseInt(s); } if(status) System.out.println(n + " IS A CIRCULAR PRIME."); else System.out.println(n + " IS NOT A CIRCULAR PRIME."); } public static boolean isPrime(int num){ int f = 0; for(int i = 1; i <= num; i++) if(num % i == 0) f++; return (f == 2); } }
Output
OUTPUT 1: N = 131 131 311 113 131 IS A CIRCULAR PRIME. OUTPUT 2: N = 197 197 971 719 197 IS A CIRCULAR PRIME. OUTPUT 3: N = 1193 1193 1931 9311 3119 1193 IS A CIRCULAR PRIME. OUTPUT 4: N = 29 29 92 29 IS NOT A CIRCULAR PRIME.
