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Python Programs - Looping Statements

Count how many times a digit occurs in a number - Python Program

Example 1 :

Python 
# Count digit frequency

num = input("Enter a number: ")
digit = input("Enter digit to count: ")

count = 0
for ch in num:
    if ch == digit:
        count += 1

print(f"Digit '{digit}' occurs {count} times in {num}.")

Output

 
OUTPUT  :
Enter a number: 1123451141
Enter digit to count: 1
Digit '1' occurs 5 times in 1123451141.

Explanation

  • Takes number as string to allow easy iteration.
  • Compares each character with the given digit.
  • Increments count if match found.

Example 2 : Advanced Program

Python 
def count_digit_occurrences(number, digit_to_count):
    """
    Counts how many times a specific digit occurs in a given number.

    Args:
        number (int): The integer in which to search for the digit.
        digit_to_count (int): The digit to count occurrences of.

    Returns:
        int: The number of times the digit_to_count appears in the number.
    """
    if not isinstance(number, int) or not isinstance(digit_to_count, int):
        raise TypeError("Both 'number' and 'digit_to_count' must be integers.")
    if not 0 <= digit_to_count <= 9:
        raise ValueError("'digit_to_count' must be a single digit (0-9).")

    count = 0
    # Convert the number to a string to easily iterate through its digits
    num_str = str(number)
    
    # Convert the digit to count to a string for comparison
    digit_str = str(digit_to_count)

    for char in num_str:
        if char == digit_str:
            count += 1
    return count

# Example Usage and Output
if __name__ == "__main__":
    num = 1232142
    digit = 2
    occurrences = count_digit_occurrences(num, digit)
    print(f"The digit {digit} appears {occurrences} times in the number {num}.")

    num2 = 78907
    digit2 = 7
    occurrences2 = count_digit_occurrences(num2, digit2)
    print(f"The digit {digit2} appears {occurrences2} times in the number {num2}.")

    num3 = 5555
    digit3 = 5
    occurrences3 = count_digit_occurrences(num3, digit3)
    print(f"The digit {digit3} appears {occurrences3} times in the number {num3}.")

    num4 = 100
    digit4 = 0
    occurrences4 = count_digit_occurrences(num4, digit4)
    print(f"The digit {digit4} appears {occurrences4} times in the number {num4}.")

Output

 
OUTPUT  :
The digit 2 appears 3 times in the number 1232142.
The digit 7 appears 2 times in the number 78907.
The digit 5 appears 4 times in the number 5555.
The digit 0 appears 2 times in the number 100.

Explanation

count_digit_occurrences(number, digit_to_count) function:

  • This function takes two integer arguments: number(the integer to analyze) and digit_to_count (the specific digit whose occurrences are to be counted).
  • Input Validation:It includes checks to ensure both inputs are integers and that digit_to_count is a single digit between 0 and 9.
  • Conversion to String:The core idea is to convert the number into a string (num_str). This allows for easy iteration over each character (which represents a digit) within the number. The digit_to_count is also converted to a string (digit_str) for direct comparison.
  • Iteration and Counting:The program then iterates through each char in num_str. If a char matches digit_str, a count variable is incremented.
  • Return Value:Finally, the function returns the count, representing the total occurrences of the specified digit.

 

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