Conditional Constructs in Java

Chapter 9

Conditional Constructs in Java

Class 9 - Logix Kips ICSE Computer Applications with BlueJ

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Java Programs - Check Pythagorean Triplet

Write a program in Java to accept three numbers and check whether they are Pythagorean Triplet or not. The program must display the message accordingly. [Hint: h²=p²+b²]

Java

import java.util.Scanner;
 
public class PythagoreanTriplet {
    public static void main(String[] args) {
 
        Scanner sc = new Scanner(System.in);
 
        System.out.print("Enter first number: ");
        int a = sc.nextInt();
 
        System.out.print("Enter second number: ");
        int b = sc.nextInt();
 
        System.out.print("Enter third number: ");
        int c = sc.nextInt();
 
        int h, p, base;
 
        // Find the largest number (hypotenuse)
        if (a >= b && a >= c) {
            h = a;
            p = b;
            base = c;
        } else if (b >= a && b >= c) {
            h = b;
            p = a;
            base = c;
        } else {
            h = c;
            p = a;
            base = b;
        }
 
        // Check Pythagorean condition
        if ((h * h) == (p * p + base * base)) {
            System.out.println("The numbers form a Pythagorean Triplet.");
        } else {
            System.out.println("The numbers do NOT form a Pythagorean Triplet.");
        }
 
        sc.close();
    }
}

Output

Output 1 : 
SAMPLE INPUT : 
Enter first number: 3
Enter second number: 4
Enter third number: 5

SAMPLE OUTPUT : 
The numbers form a Pythagorean Triplet.

Output 2 : 
SAMPLE INPUT : 
Enter first number: 6
Enter second number: 8
Enter third number: 10

SAMPLE OUTPUT : 
The numbers form a Pythagorean Triplet.

Output 3 : 
SAMPLE INPUT : 
Enter first number: 2
Enter second number: 3
Enter third number: 4

SAMPLE OUTPUT : 
The numbers do NOT form a Pythagorean Triplet.

Explanation

1. Input Three Numbers

Accepts three integers from the user.

2. Identify the Hypotenuse

The largest number is taken as the hypotenuse (h).

3. Apply Pythagorean Formula

h²= p²+ b²

if ((h * h) == (p * p + base * base))

4. Display Result

Prints whether the numbers form a Pythagorean Triplet or not.